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If the remainder R(x)=ax+b is ontained b...

If the remainder `R(x)=ax+b` is ontained by dividing the polynomial `x^(100)` by the polynomial `x^(2)-3x+2` then (A) `a=2^(100)-1` (B) `b=2(2^(99)-1)` (C) `b=-2(2^(99)-1)` (D) `a=2^(100)`

A

`a=2^(100)-1`

B

`b=2(2^(99)-1)`

C

`b=-2(2^(99)-1)`

D

`a=2^(100)`

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