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If `(x_1, y_1)&(x_2, y_2)` are the solutions of the equaltions, `(log)_(225)(x)+log_(64)(y)=4a n d(log)_x(225)-(log)_y(64)=1,` `(log)_(225)x_1dot(log)_(225)x_2=4` b. `(log)_(225)x_1+(log)_(225)x_2=6` c. `|(log)_(64)y_1-(log)_(64)y_2|=2sqrt(5)` d. `(log)_(30)(x_1x_2y_1y_2)=12`

A

`log _(225)x_(1).log_(225)x_(2)=4`

B

`log_(225)x_(1)+log _(225)x_(2)=6`

C

`|log_(64)y_(1)-log_(64)y_(2)|=2sqrt(5)`

D

`log _(3)(x_(1)x_(2)y_(1)y_(2))=12`

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