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If `alpha,beta` be the roots of the equation `(x-a)(x-b)+c=0(c!=0),` then the roots of the equation `(x-c-alpha)(x-c-beta)=c` are `aa n db+c` (b) `a+ba n db` `a+ca n db+c` (d) `a-ca n db-c`

A

`a and b +c`

B

`a+b and b`

C

`a +c and d+c`

D

`a-c and b-c`

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