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Then sum sum(r=1)^(50) r.(2^(r)+2^(50-r)...

Then sum `sum_(r=1)^(50) r.(2^(r)+2^(50-r))` equals

A

`25(2^(50)-1)`

B

`50(2^(50)-1)`

C

`25(2^(51)-1)`

D

`50(2^(51)-1)`

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