Home
Class 12
BIOLOGY
The movement of a molecule across a typi...

The movement of a molecule across a typical plant cell (about `50mum`) takes approximately 2.5s. At this rate calculate how many years it would take for the movement of molecules over a distance of 1 m within a plant by diffusion alone?

Text Solution

Verified by Experts

The correct Answer is:
`1.58xx10^(-3)` years
Promotional Banner

Similar Questions

Explore conceptually related problems

The movement of molecule across a typical plant cell ( about 50 mum ) takes place approximately ______ seconds.

Approximate time required by a diffusing particle across a plant cell about 50 mum is

If the water molecules in 1 g of water were distributed uniformaly over the surface of the earth, how many molecules would there be in 1 m^(2) of the earth's surface (radius of the earth = 64 km)?

A wave pulse is travelling on a string of linear mass density 10gcm^(-1) under a tension of 1kg wt. Calculate the time taken by the pulse to travel a distance of 50cm on the string. Take g=10m//s^(2).

A particle starts with an initial velocity 2.5 m/s along the positive x direction and it accelerates uniformly at the rate 0.50 m/s^2 . A. Find the distance travelled by it in the first two seconds. b.How much time does it take to reach the velocity 7.5 m/s ? c. How much distance will it cover in reaching the velocity 7.5 m/s?

A tyre has two punctures. The first puncture alone would have made the tyre flat in 9 minutes and the second alone would have done it in 6 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat? a. 1 1/2 minutes b. 3 1/2 minutes c. 3 3/5 minutes d. 4 1/4 minutes

A water hose pipe of cross-sectional area 5cm^(2) is used to fill a tank of 120L . It has been observed that it takes 2 min to fill the tank. Now, a nozzel with an opening of cross-sectional area 1cm^(2) is attached to the hose. The nozzel is held so that water is projected horizontally from a point 1m above the ground. The horizontal distance over which the water can be projected is (Take g=10m//s^(2)) .