The values of 't' so that `(x^2 -8x+20)/((sin t) x^2 + 2(1+sint)x + 9 sin t + 4 <0, x in R` is/are

x = sin t, y = cos 2 t .

Find the value of t, where t in [-pi/2,pi/2] so that 2sint=(5x^2-2x+1)/(3x^2-2x-1),x in R

The maximum value of cos (int_(2x)^(x^(2)) e^t sin^2 " t dt ")

The maximum value of cos (int_(2x)^(x^(2)) e^t sin^2 " t dt ")

Find the slope of the tangent to the curve x=2(t-sin t) and y = 2(1-cost) at t= (pi)/(4)

If e^(( cos^2 x + cos^4x+ cos ^6 x + ……..oo ) log_e 2) satisfies the equation t^2 - 9t + 8=0 , then the value of ( 2 sin x)/( sin x + sqrt(3) cos x) ( 0 lt x lt (pi)/(2)) is

The correct value of the parameter t of the identity 2(sin ^(6)x + cos ^(6) x)+t (sin ^(4)x+ cos ^(4)x)=-1 is-

dx/dt + x cos t = 1/2 sin 2 t

x = "sin" t, y = "cos" 2t