`(sintheta-costheta+1)/(sintheta+costheta-1)=sectheta+tantheta`

Prove that: (sintheta-costheta+1)/(sintheta+costheta-1)=1/(sectheta-tantheta)

Prove the following identities : (sintheta-costheta+1)/(sintheta+costheta-1)=1/(sectheta-tantheta)

Prove that (sintheta-costheta+1)/(sintheta+costheta-1)=1/(sectheta-tantheta) , using the identity sec^2theta=1+tan^2theta

(1+sintheta-costheta)/(1+sintheta+costheta)=

(1+sintheta-costheta)/(1+sintheta+costheta) =

Prove the following : (sintheta-costheta+1)/(sintheta+costheta-1)=(1)/(sectheta-tantheta) .

Prove that: (1+sintheta-costheta)/(1+sintheta+costheta)=tantheta/2

Prove that: (1+sintheta-costheta)/(1+sintheta+costheta)=tantheta/2

If (sintheta-costheta+1)/(sintheta+costheta-1)=(x)/(tantheta-sectheta+1) then x =