A body with zero initial velocity slips from the top of an inclined plane forming an angle `alpha` with the horizontal. The coefficient of friction `mu` between the body and the plane increases with the distance s from the top according to the law `mu = bs`. After what distance the body will stop.

A body with zero initial velocity slips from the top of an inclined plane forming an angle alpha with the horizontal. The coefficient of friction mu between the body and the plane increases with the distance l from the top according to the law mu = bl . The body stops before it reaches the end of the plane. Determine the time t from the beginning of motion of the body to the moment when it comes to rest.

A body is moving down a long inclined plane in inclination 45^(@) with horizontal. The coefficient of friction between the body and the plane varies as mu=x//2 , where x is the distance moved down the plane. Initially x=0 & v=0 .

A body is moving down a long inclined plane of inclination 45^(@) with horizontal. The coefficient of friciton between the body and the plane varies as mu = x//2 , where x is the distance moved down the plane. Initially x=0 & v=0

A body takes just twice the time as long to slide down a plane inclined at 30^(@) to the horizontal as if the plane were frictionless. The coefficient of friction between the body and the plane is

A body is moving down along inclined plane of angle of inclination theta The coefficient of friction between the body and the plane varies as mu=0.5x where x is the distance moved down the plane. The body will have the maximum velocity when