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sech^(-1)(sin theta)=...

sech^(-1)(sin theta)=

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If: cos^(-1) (sin theta) = sin^(-1) (cos theta) , then: theta =

(1)/(csc theta-cot theta)-(1)/(sin theta)=(1)/(sin theta)-(1)/(csc theta+cot theta)

Prove that (1+cos theta)/(sin theta)=(1+sin theta+cos theta)/(1+sin theta-cos theta) .

(sin theta-cos theta+1)/(sin theta+cos theta-1)=(1+sin theta)/(cos theta)

Prove that (1)/(2){(sin theta)/(1+cos theta)+(1+cos theta)/(sin theta)}=(1)/(sin theta)

((sin theta+cos theta-1)/(sin theta-cos theta+1))(1+sin theta) =

(1-cos theta)/(sin theta)=(sin theta)/(1+cos theta)