[" A function "f" is defined by "f(x)=int_(0)^(1)cos t cos(x-t)dt,0<=x<=2 pi," then maximum value of "],[14f(x)" is "]

A function f is defined by f(x)=int_(0)^(pi)cos t cos (x-t)dt, 0 lexle2pi then the minimum value of f(x) is

A function fis defined by f(x)=int_(0)^( pi)cos t cos(x-t)dt,0<=x<=2 pi then which of the following.hold(s) good?

A function f is defined by f(x) = int_0^pi cos t cos(x-t)dt,0 <= x <= 2 pi then which of the following.hold(s) good?

A function f is defined by f(x) = int_0^pi cos t cos(x-t)dt,0 <= x <= 2 pi then which of the following.hold(s) good?

A function is defined by f(x) = int_0^pi cos t cos(x-t)dt,0 <= x <= 2 pi then which of the following equals?

If a differentiable function f(x) satisfies f(x)=int_(0)^(x)(f(t)cos t-cos(t-x))dt then value of (1)/(e)(f''((pi)/(2))) is

A differentiable function satisfies f(x)=int_(0)^(x){f(t)cost-cos(t-x)}dt. Which is of the following hold good?

Let f(x) be a differentiable function satisfying f(x)=int_(0)^(x)e^((2tx-t^(2)))cos(x-t)dt , then find the value of f''(0) .

Let f(x) be a differentiable function satisfying f(x)=int_(0)^(x)e^((2tx-t^(2)))cos(x-t)dt , then find the value of f''(0) .

Let f(x) be a differentiable function satisfying f(x)=int_(0)^(x)e^((2tx-t^(2)))cos(x-t)dt , then find the value of f''(0) .