Photons of frequency v fall on a metal surface for which the thershold frequency is `v_(0)(vge v_(0))`. Then,

Photons of frequency, v, fall on metal surface for which the threshold frequency is v_(0) . Then

A photon of frequency v is incident on a metal surface whose threshold frequency is v_(0) . The kinetic energy of the emitted photoelectrons will be

A photon of frequency v causes photo electric emission from a surface with threshold frequency v_(0) . The de-Broglies wavelength (lambda) of the photo electron emitted is given by:

A photon of frequency v causes photo electric emission from a surface with threshold frequency v_(0) . The de-Broglies wavelength (lambda) of the photo electron emitted is given by:

Radiation of frequency v=9v_(0) is incident on a metal surface, having threshold frequency v_(0) . The maximum velocity of the ejected photoelectrons is 6xx10^(6)m//s . What will be the maximum velocity of the ejected photoelectrons , if v is reduced to 3v_(0) ?

Light of frequency .25 v_0 is incident on a metal surface of threshold frequency 2 v_0 . If its frequency is halved and intensity is made three times then find the new value of photoelectric current.

Light of frequency 4 v_(0) is incident on the metal of the threshold frequency v_(0) . The maximum kinetic energy of the emitted photoelectrons is