[" OA and "OB" are two perpendicular straight lines.A straight line "AB" is drawn in such a manner that "OA+OB=8" ."],[" Find the locus of the mid point of "AB" ."]

A straight line through the point (1,1) meets the X-axis at A and Y-axis at B. The locus of the mid-point of AB is

A straight line through the point (1,1) meets the X-axis at A and Y-axis at B. The locus of the mid-point of AB is

If OA and OB are two perpendicular chords of the circle r=a cos theta+b sin theta epassing through origin,then the locus of the mid point of AB is :

Two fixed point A and B are taken on the cordinate axes such that OA = a and OB = b. Two variable points A' and B' are taken on the same axes such that OA'+OB' = OA + OB. Find the locus of the point of intersection of AB' and A'B.

The straight line cuts the coordinate axes at A and B. if the mid point of AB is (3,2) the find the equation of AB.

AB and CD are two parallel chords of a circle and lines CA and DB intersect each other at O. Show that OA = OB.