" 15."px-5q+pq-5x

Factorise : px-5q-5x+pq

If int(px cos5x-q sin5x)/(x^2)dx=(q sin5x)/(x)+C , then p and q may be (where C is constant of integration)

Subtract 4p^2q – 3pq + 5pq^2 – 8p + 7q – 10 from 18 – 3p – 11q + 5pq – 2pq^2 + 5p^2q

Simplify (2.5 p-1.5 q)^2-(1.5 p-2.5 q)^2

Subtract 4p^2 q - 3pq + 5 pq^2 - 8p + 7q - 10 from 18-3p - 11 + 5pq - 2pq^2 + 5p^2 q

Factorize: 15pq+15+9q+25p

Add: 5px+7q-r,2px+3r and =px+2q+r.

Subtract: 4pq – 5q^2 – 3p^2 from 5p^2 + 3q^2 – pq

Show that: (9p - 5q)^2 + 180 pq = (9p+ 5q)^2