The number of ways in which we can choose a committee from four men and six women, so that the committee includes atleast two men and exactly twice as many women as men is

The number of ways in which we can choose a the committee from four men and six women so that the committee includes at least two men and exactly twice as many women as women as men is :

[" The number of ways in which we can choose a committee from "],[" four men and six women so that the committee includes at least "],[" two men and exactly twice as many women as men is "],[[" (A) "49," (B) "126," (C) "128," (D) "94]]

Find the number of ways in which we can choose a committee from 4 men and 6 women, so that the committee includes two men exactly twice as many women as men

Find the number of ways of forming a committee of 5 members out of 5 men and 5 women so that in the committee there is atleast one man

Find the number of ways of forming a committee of 5 members out of 5 men and 5 women so that in the committee women will be in a majority

In how many ways can a committee of 5 made out 6 men and 4 women containing atleast one woman?

A committee of 6 is to be choosen from 10 men and 7 women so as to contain atleast 3 men and 2 women. In how many different ways can this be done?