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Two years ago, a father was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son. Find the present ages of father and son.

Two years ago,a father was five xx as old as his son.Two years later,his age will be 8 more than three xx the age of the son.Find the present ages of father and son.

The age of a man is twice the square of the age of his son . After eight years , the age of the man will be 4 years more than three times the age of his son. Find their present age.

The age of a father is twice the square of the age of his son. Eight years hence, the age of his father will be 4 years more than 3 times the age of the son. Find their present ages.

The age of a father is twice the square of the age of his son. Eight years hence, the age of his father will be 4 years more than 3 times the age of the son. Find their present ages.

Two years ago a father was five times as old as his son. Two years later, his age will be 8 years more than three times the age of the son. Represent this situation algebraically and graphically .

The age of a man is twice the square of the age of his son.Eight years hence,the age of the man will be 4years more than three times of the age of his son.Find their present ages.

The age of a man is twice the square of the age of his son.Eight years hence,the age of the man will be 4 years more than three xx the age of his son.Find their present ages.

The age of a father 8 years ago was 5 times that of his son 8 years. Hence, his age will be 8 years more than twice the age of his son. Then the present age of fatherd is ………years.