" (b) "m^(6)+n^(6)

(m+n)(m+n)(m+n)(m-n)(m-n)(m-n)=m^(6)-n^(6) . (True/False)

Factorise : m^(6)-64n^(6)

Put into another form using a^(m)divb^(m)=((a)/(b))^(m) 5^(6)div(-2)^(6)

(6m^(2)-5n)^(2)

If m and n are positive integers,then the digit in the units place of 5^(n)+6^(m) is always (a) 1( b) 5( c) 6 (d) n+m

If 6m-n=3m+7n , then find the value of (m^(2))/(n^(2))

If 6m-n=3m+7n , then find the value of (m^(2))/(n^(2))

If n is any natural number,then 6^(n)-5^(n) always ends with (a) 1 (b) 3 (c) 5 (d) 7 [Hint: For any n in N,6^(n) and 5^(n) end with 6 and 5 respectively.Therefore,6^(n)-5^(n) always ends with 6-5=1.