[" BD and "CE" are bisectors of "/_B" and "/_C" of an isosceles "/_ABC" with "AB=AC" Prove "],[" that "BD=CE" ."]

BD and CE are bisectors of /_B and /_C of an isosceles hat harr ABC with AB=AC. Prove that BD=CE .

AD is the bisector of /_BAC of /_\ABC , where D is a point on BC. Prove that (BD)/(DC)=(AB)/(AC) .

In a Delta ABC, the bisectors of ext /_B and ext /_C meet at D. If BD>CD, then prove that AC>AB.

ABC is an isosceles triangle with AB =AC and BD,CE are its two medians. Show that BD=CE .

ABC is an isosceles triangle with AB =AC and BD,CE are its two medians. Show that BD=CE .

In DeltaABC , BD and CE are perpendicluars to the sides AC and AB respectively and BD = CE. Prove that DeltaBCD~=DeltaCBE .

In DeltaABC, AB = AC and the bisectors of angleB and angleC meet AC and AB at point D and E respectively. Prove that BD = CE .

In DeltaABC, AB = AC and the bisectors of angleB and angleC meet AC and AB at point D and E respectively. Prove that BD = CE .

In the given figure, AB = AC and AD = AE. Prove that: BD = CE

If D and E are points on sides AB and AC respectively of a ABC such that DEBC and BD=CE. Prove that ABC is isosceles.