Results on Population : Population after n years n सालों बाद की आबादी

Results on Depreciation : Value of the machine after n years ???? ???? ?? ????? n ????? ???

Statement I: If the annual increase in the population be 20% and present population be 10,000 then the population after 4 years is 20,736 .Statement II: the original population of a location be p and the annual growth rate be r%. The population after n years is P(1+(r)/(100))^(n).

The population of a town in the first year increases by 10% in the next year it decreases by 10%. Once again in the third year it icnrease by 10% and in the fourth year it decrease by 10%. If the present population be 20,000 then the population after four years will be :

The population of a city increased 30% in the first year and decreased by 15% in the next year. If the present population is 11,050 then the population 2 years ago was: एक शहर की आबादी पहले साल 30% बढ़ी तथा अगले वर्ष 15% कम हो गयी | यदि वर्तमान आबादी 11,050 है, तो 2 वर्ष पहले कितनी आबादी थी ?

If the annual increase in the population be 20% and the present population be 10,000. What will be the population after 3 years hence ?

Population n years ago n ????? ???? ?? ?????

Formula 3 Let P be the population of a city or a town at the beginning of a certain year. if the population decreases at the rate of R% per annum then population after n years = P (1- R/100)^n