Simplify: `(11)/2x^2y-9/4x y^2+1/4x y-1/(14)y^2x+1/(15)y x^2+1/2x y`

Simplify: (11)/(2)x^(2)y-(9)/(4)xy^(2)+(1)/(4)xy-(1)/(14)y^(2)x+(1)/(15)yx^(2)+(1)/(2)xy

Simplify: (3x+2y)(4x+3y)-(2x-y)(7x-3y)

Simplify: (3x+2y)(4x+3y)-\ (2x-y)(7x-3y)

Simplify (2x + y) (1 + 4x + 3y) -6x (x + y)

Simplify: (x-y)(x+y)x^(2)+y^(2))(x^(4)+y^(5))2x-1)(2x+1)(4x^(2)+1)(16x^(4)+1)(7m-8n)^(2)+(7m+8n)^(2)

Simplify: (i) (x-y)(x+y)x^2+y^2)\ (x^4+y^4) (ii) (2x-1)\ (2x+1)(4x^2+1)(16 x^4+1) (iii) (7m-8n)^2+(7m+8n)^2

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

If 1/x-1/y=4 then (2x+4xy-2y)/(x-y-2xy)=

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (a) (x^2+y^2)^2=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (x^2-y^2)=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)