`int(log_e(x+1)/((x+1)dx`

Evaluate : int(log_e(x+1))/((x+1)^2) dx

int (1+log_e x)/x dx

int log((1)/(e^(x)))dx

int log(e^(x)+1)(e^(x))dx

int log_(e)(1+x)dx

If int_(log 2)^(x)(1)/(e^(x)-1)dx = log""(3)/(2) , show that x = log 4

int(log_e(x+1)-log_ex)/(x(x+1))dx is equal to (A) -1/2[log(x+1)^2-1/2logx]^2+log_e(x+1)log_ex+C (B) -[(log_e(x+1)-log_ex]^2 (C) c-1/2(log(1+1/x))^2 (D) none of these

int(log_e(x+1)-log_ex)/(x(x+1))dx is equal to (A) -1/2[log(x+1)^2-1/2logx]^2+log_e(x+1)log_ex+C (B) -[(log_e(x+1)-log_ex]^2 (C) c-1/2(log(1+1/x))^2 (D) none of these