A projectile is given an initial velocity `hati+2 hatj`.The cartesin equation of its path is `(g=10ms^(-2))`

A projectile is given an initial velocity of hat i+2hatj . The Cartesian equation of its path is (g= 10 m/s^2

A projectile is given an initial velocity of (hat(i)+2hat(j)) The Cartesian equation of its path is (g = 10 ms^(-1)) ( Here , hati is the unit vector along horizontal and hatj is unit vector vertically upwards)

A projectile is given an initial velocity of (hat(i)+2hat(j)) The Cartesian equation of its path is (g = 10 ms^(-1)) ( Here , hati is the unit vector along horizontal and hatj is unit vector vertically upwards)

" A projectile is given an initial velocity "hat i+2hat j" .The cartesian equation of its path is "[" take "g=10m/s^(2)]

A projectile is given an initial velocity of hat t + 2.hatj . Find the cartisian equation of its path. (g = 10 ms^-1) .

A projectile is given an initial velocity of ( hat (i) + 2 hat (j)) ms^(-1) . The equation of its path is (g= 10 ms^(-2))

A particle is projected with initial velocity of hati+2hatj . The eqaution of trajectory is (take g=10ms^(-2))

A projectile is given an initial velocity of (hati+2hatj)m/s , where hati is along the ground and hatj is along the vertical. If g=10m/s^-2 , the equation of its trajectory is