A certain amount of mono - atomic ideal gas undergoes a process `rhoU^(n)`= constant where `rho` is density of gas and U is internal energy of the gas.It is found that the ratio `(W)/(deltaU)` for this process is `2/3`. Find the value of n.

An ideal monatomic gas undergoes process PV^(1.25) = constant .Then

A certain amount of an ideal monoatomic gas undergoes a thermodynamic process such that VT^(2)= constat where V= volume of gas, T= temperature of gas. Then under process

A certain amount of ideal monoatomic gas undergoes a process given by TV^(1//2) = constant. The molar specific heat of the gas for the process will be given by

V-T graph of a process of monoatomic ideal gas is shown in figure. Change in internal energy of the gas is zero in process(s)-

One mole of an ideal monatomic gas undergoes a process described by the equation PV^(3) = constant. The heat capacity of the gas during this process is

One mole of a mono atomic gas of molar mass M undergoes a cyclic process as shown in the figure. Here rho is density and P is pressure of the gas. (a) Calculate the heat rejected by the gas in one complete cycle. (b) Find the efficiency of the cycle.

[H_(2)" gas undergoes process where "PV^(2)=" constant.The ratio of work done by gas to modulus of change in "],[" its internal energy as the gas expands is "(2)/(N).N" is equal to "]

Two moles of an ideal monoatomic gas undergoes a process VT = constant. If temperature of the gas is increased by DeltaT = 300K , then the ratio ((DeltaU)/(DeltaQ)) is