How many moles of acidified \(K_{2}Cr_{2}O_{7}\) is required to liberated "6" moles of \(I_{2}\) from an aqueous solution of \(I^{-}\) ...........

One mole of acidified K_(2)Cr_(2)O_(7) in reaction with excess KI will liberate …… moles of I_(2)

Colour of acidified K_(2)Cr_(2)O_(7) is not changed by:

One mole of acidified K_(2)Cr_(2)O_(7) on reaction with excess of KCl will liberate….., moles of I_(2) .

How many moles of K_(2)Cr_(2) O_(7) are reduced by 1 mole of formic acid -

SO_(2) reduces acidified K_(2)Cr_(2)O_(7) to

Hydrogen sulphide truns an acidified K_(2)Cr_(2)O_(7)

The number of moles of \(K_{2}Cr_{2}O_{7}\) required to oxidise one mole of \(Sn^{+2}\) to "1" mole of\(Sn^{+4}\) in acidic medium is "1/x" .The value of x is (A) 1/3 (B) 3 (C) 6 (D) 2