A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower,It hits the ground after some time with a velocity of 80m/s .The height of the tower is : `(g=10m/g^(2))`

A ball is thrown vertically downward with velocity of 20 m/s from top of tower. It hits ground after some time with a velocity of 80 m /s . Height of tower is

A ball is thrown vertically upward with velocity 20 m//s from a tower of height 60 m. After how much time and with what velocity will it strike the ground?

[" A ball is thrown vertically downward "],[" with velocity u from the top of a tower."],[" It strikes the ground with a velocity "3u" ."],[" The time taken by the ball to reach the "],[" ground is given by "]

A ball is thrown vertically upwards from the top of a tower with a velocity of 10m/s. If the ball falls on the ground after 5 seconds, the height of the tower will be? (use g=10m/ s^(2) )

A ball is thrown upward with speed 10 m/s from the top to the tower reaches the ground with a speed 20 m/s. The height of the tower is [Take g=10m//s^(2) ]

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2))

The ball is projected vertically down with a velocity of 10sqrt(3)m/s from a height of 20m .On the hitting the ground if it loses 40% of its energy the height to which it bounces is (g=10ms^(-2))

The ball is projected vertically down with a velocity of 10sqrt(3)m/s from a height of 20m .On the hitting the ground if it loses 40% of its energy the height to which it bounces is (g=10ms^(-2))

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.