Show that all chords of the curve `3x^2-y^2-2x+4y=0,` which subtend a right angle at the origin, pass through a fixed point. Find the coordinates of the point.

All chords of the curve 3x^(2)-y^(2)-2x+4y=0 which subtend a right angle at the origin,pass through the fixed point

Chords of the curve 4x^(2) + y^(2)- x + 4y = 0 which substand a right angle at the origin pass thorugh a fixed point whose co-ordinates are :

All the chords of the curve 2x^(2)+3y^(2)-5x=0 which subtend a right angle at the origin are concurrent at :

Statement-1: All chords of the curve 3x^(2)-y^(2)-2x+4y=0 which subtend a right angle at the origin pass through a fixed point. Statement-2: The equation ax+by+c=0 represents a family of straight lines passing through a fixed point iff there is a linear relation between a, b and c.

All the chords of the curve 2x^(2) + 3y^(2) - 5x =0 which subtend a right angle at the origin are concurrent at :

All chords.of the curve x^(2)+y^(2)-10x-4y+4=0 which make a right angle at (8,-2) pass through

Show that all chords of a parabola which subtend a right angle at the vertex pass through a fixed point on the axis of the curve.

Show that all the chords of the curve 3x^2 – y^2 – 2x + 4y = 0 which subtend a right angle at the origin are concurrent. Does this result also hold for the curve, 3x^2 + 3y^2 – 2x + 4y = 0 ? If yes, what is the point of concurrency and if not, give reasons.