If the chord, joining two points whose eccentric angles are `alpha and beta`, cuts the major axis ofthe ellipse `x^2/a^2 + y^2/b^2=1` at a distance c fromn the centre, then `tan alpha//2.tan beta//2` is equal to

If the chord, joining two points whose eccentric angles are alpha and beta , cuts the major axis ofthe ellipse x^2/a^2 + y^2/b^2=1 at a distance c from the centre, then tan alpha//2.tan beta//2 is equal to

If the chord, joining two points whose eccentric angles are alpha and beta , cuts the major axis ofthe ellipse x^2/a^2 + y^2/b^2=1 at a distance c from the centre, then tan alpha//2.tan beta//2 is equal to

If the chord,joining two points whose eccentric angles are alpha and beta, cuts the major axis ofthe ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at a distance crromn the centre,then tan alpha/2.tan beta/2 is equal to

If the chord joining two points whose eccentric angles are alpha and beta cut the major axis of an ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at a distance from the centre then tan (alpha)/(2).tan (beta)/(2) =

If (alpha-beta)=(pi)/(2) ,then the chord joining the points whose eccentric angles are alpha and beta of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 touches the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=(1)/(k) , then ( 5k^(2)+2) is equal to

IF alpha , beta are eccentric angles of end points of a focal chord of the ellipse x^(2)/a^(2) + y^(2)/b^(2) =1 then tan(alpha /2) tan (beta/2) is equal to

If any two chords be drawn through two points on the major axis of the ellipse x^2/a^2+y^2/b^2=1 equidistant from the centre prove that tan""alpha/2 tan""beta/2 tan""gamma/2=1 where alpha,beta,gamma,delta are the eccentricity angles of the extremities of the chord.

If a chord joining two points whose eccentric angles are alpha and beta so that tan alpha.tan beta=-(a^(2))/(b^(2)), subtend an angle theta at the centre of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 then theta=

If the chord joining points P(alpha) and Q(beta) on the ellipse ((x^2)/(a^2))+((y^2)/(b^2))=1 subtends a right angle at the vertex A(a ,0), then prove that tan(alpha/2)tan(beta/2)=-(b^2)/(a^2)dot