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If one of the lines of m y^2+(1-m^2)x y-...

If one of the lines of `m y^2+(1-m^2)x y-m x^2=0` is a bisector of the angle between the lines `x y=0` , then `m` is 3 (b) 2 (c) `-1/2` (d) `-1`

A

1

B

2

C

`-1//2`

D

-1

Text Solution

Verified by Experts

Here , `my(y-mx)+x(y-mx)=0`
or `(y-mx)(my+x)=0`
So the lines are `y=mxory=(-1//m)x`. The bisectors between the lines `xy=0` are` y=xandy=-x`. Therefore , `m=1,-1`.
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