Sum of the areas of two squares is `544 m^(2)`. If the difference of their perimeters is 32 m. find the sides of two squares.

Sum of the areas of two squares is 468 m^(2) If the difference of their perimeters is 24m, find the sides of the two squares.

The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field. OR Sum of the areas of two squares is 468m^(2) . If the difference of their perimeters is 24m, find the sides of two squares.

Sum of the ares of two squares is 544 m^2 . if the difference of their perimeters is 32. find the sides of two squares.

Sum of the ares of two squares is 544 m^2 . if the difference of their perimeters is 32. find the sides of two squares.

Sum of the ares of two squares is 544 m^2 . if the difference of their perimeters is 32. find the sides of two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.