A particle of mass m is projected with a velocity `mu` at an angle of `theta` with horizontal.The angular momentum of the particle about the highest point of its trajectory is equal to :

A particle of mass m is projected with a velocity v at an angle of theta with horizontal. The angular momentum of the particle at the highest point of its trajectory is equal to :

A particle of mass m is projected with a speed u at an angle theta with the horizontal. Find angular momentum of particle after time t about point of projection.

A body of mass m is projected with a velocity u at an angle theta with the horizontal. The angular momentum of the body, about the point of projection, when it at highest point on its trajectory is

A body of mass m is projected with a velocity u at an angle theta with the horizontal. The angular momentum of the body, about the point of projection, when it at highest point on its trajectory is

A particle of mass m is projected with velocity v at an angle theta with the horizontal. Find its angular momentum about the point of projection when it is at the highest point of its trajectory.

A particle of mass m is projected with velocity v at an angle theta with the horizontal. Find its angular momentum about the point of projection when it is at the highest point of its trajectory.

A particle of mass m is projected with velocity v making an angle of 45 with horizontal. Magnitude of angular momentum of particle about the point of projection when the particle is at its maximum height is