[" Question "15:],[tan^(3)2x sec2x],[" Answer "]

General solution of tan^(2)x+sec2x=1 is

Integrate the functions quad tan^(3)2x sec2x

(tan 2x)/(1+ sec 2x) = tan x

Find the integral tan ^3 2 x sec 2 x^

Differentiate tan2x+sec2x

If |[sec^2x, tanx, tan^2x] , [tan^2x, sec^2x, tanx] , [tanx, tan^2x, sec^2x]| is expanded in the power of tanx then the constant is

int sec^(2)x-tan^(2)x

Evaluate: (i) int tan^(3)x sec^(2)xdx (ii) int tan x sec^(4)xdx

Find the integrals of the function: tan^3(2x) sec 2x