If `)-4,0)` and `(1,-1)` are two vertices of a triangle of area `4s qdotu n i t s ,` then its third vertex lies on `y=x` (b) `5x+y+12=0` `x+5y-4=0` (d) `x+5y+12=0`

If (2, -2),(-1,2), (3,5) are the vertices of a triangle then the equation of the side not passing through (2,-2) is (A) x + 2y +1 = 0 (B) 2x - y- 4= 0 (C) X-3y -3= 0 (D) 3x – 4y + 11 = 0

The sides of a triangle are 3x+4y,4x+3y and 5x+5y units,where x,y>0. The /_ is

Two vertices of triangle are (-2,-1) and (3,2) and third vertex lies on the line x+y=5. If the area of the triangle is 4 square units, then the third vertex is a. (-0,50 or (4,1) b. (5,0) of (1,4) c. (5,0) or (4,1) d. (o,5) or (1,4)

If two vertices of a triangle are (-2,3) and (5,-1) the orthocentre lies at the origin, and the centroid on the line x+y=7 , then the third vertex lies at (a) (7,4) (b) (8,14) (c) (12 ,21) (d) none of these

The area of a triangle is 5. Two of its vertices are (2,1) and (3,-2). The third vertex lies on y=x+3. Find the third vertex.

The area of a triangle is 5. Two of its vertices are (2,1) and (3,-2). The third vertex lies on y=x+3. Find the third vertex.

Find the vertices of the triangle whose sides are y+2x=3, 4y+x=5 and 5y+3x=0