The `I_(1),I_(2),I_(3),I_(4)` values of an element "M" are 120 kJ/mole, `600 kJ//"mole", 1000 kJ//"mole"` and `8000 kJ//"mole"`. Then the formula of its sulphate is

The first four ionization energies of an element are 738 kJ/mole, 1450 kJ/mol, 7700 kJ/mol and 11000 kJ/mol. Identify the periodic group to which this element belongs.

The first four ionization energies of an element are 738 kJ/mole, 1450 kJ/mol, 7700 kJ/mol and 11000 kJ/mol. Identify the periodic group to which this element belongs.

The first four ionization energies of an element are 738 kJ/mole, 1450 kJ/mol, 7700 kJ/mol and 11000 kJ/mol. Identify the periodic group to which this element belongs.

Ionisation energy values of an atom are 495 , 767 , 1250 and 4540 kJ "mole"^(-1) the formula of its sulphate is

The IP of Zr is 674kJ//"mole" . The IP of Hf is

An element "X" has IP=1681 kJ/mole and EA=-333 kJ/mole then its electronegativity is

I_(1) and I_(2) of an element are "700" and 1200KJ/ mole respectively if ,1000KJ/ mole energy is supplied to the gaseous atomic element and the ionisation occur in succession,the ratio of monovalent and divalent cations.

I_(1) of an element X is 899" kJ mole"^(-1) and that of another element Y is 801" kJ mole"^(-1) . Then X and Y may be

I_1 of an element X is 899 kJ "mole"^(-1) and that of another element Y is 801kJ mole-1. Then X and Y may be