Home
Class 10
MATHS
In Delta PQR, m angle PQR = 90^(@), seg ...

In `Delta PQR, m angle PQR = 90^(@), seg QS bot hyp PR` then

A

`QS^(2) = PS xx RS`

B

`PS^(2) = QS xx PR`

C

`PR^(2) = QS xx PS`

D

`PR^(2) = QS^(2) xx PS^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • PYTHAGORAS THEOREM

    CHETAN PUBLICATION|Exercise PROBLEMS FOR PRACTICE|17 Videos

  • PYTHAGORAS THEOREM

    CHETAN PUBLICATION|Exercise ASSIGNMENT -2|8 Videos

  • PYTHAGORAS THEOREM

    CHETAN PUBLICATION|Exercise Problem Set - 2 (MCQ)|8 Videos

  • MODEL ACTIVITY SHEET

    CHETAN PUBLICATION|Exercise QUESTION|29 Videos

  • QUADRATIC EQUATIONS

    CHETAN PUBLICATION|Exercise ASSIGNMENT|12 Videos

Similar Questions

Explore conceptually related problems

In Delta PQR, angle PQR = 90^(@), "seg" QM bot hyp PR, PM = 16 and RM = 9 then QM…….

Solve the following sub questions: in Delta PQR, angle PQR = 90^(@) "seg" QS bot "hypotenuse" PR, PS = 16 , RS = 9 "find" QS

In Delta PQR, angle Q = 90^(@), PQ = QR = 5 sqrt 2 PR = 10 "then" angle P…….

Solve the following sub question in Delta ABD, angle BAD = 90^(@) seg AC bot hypo BD, B - C- D show that (i) AB^(2) = BC : BD (ii) AD^(2) = BD : CD

In the adjoining figure, angle PQR = 90^(@) "seg" QS bot side PR, PS = 4, PQ = 6. Find x,y and z.

In Delta QSR, m angle Q = 45^(@), m angle S = 90^(@) and SR =4 "find" QS

In the adjoining figure, angle QPR = 90^(@), "seg" PM bot hypotenuse QR, Q - M - R. If PM = 10, QM = 8 then find QR.

In Delta RST, angle s = 90^(@),RT = 12 m, ST = 8 m then RS=

In DeltaPQR,anglePQR=90^(@), as show in figure, seg QSbotsidePR, seg QM is angle bisector of anglePQR. Prove that : (PM^(2))/(MR^(2))=(PS)/(SR)

In Delta ABC, angle BAC = 90^(@), seg BL and seg CM are medians of Delta ABC prove that 4(BL^(2) + CM^(2)) = 5 BC^(2)