Home
Class 10
MATHS
E is a point on hypotenuse dF of Delta D...

E is a point on hypotenuse dF of `Delta DFH,` such that seg `HE bot seg DF, seg EG bot seg FH and seg EK bot seg DH` prove that,
(i) `EG^(2) = FG xx EK`
(ii) `EK^(2) = DK xx EG`

Text Solution

Verified by Experts

The correct Answer is:
x = 5, y = 2 sqrt 5 , z = 3
Promotional Banner

Topper's Solved these Questions

  • PYTHAGORAS THEOREM

    CHETAN PUBLICATION|Exercise ASSIGNMENT -2|8 Videos

  • PYTHAGORAS THEOREM

    CHETAN PUBLICATION|Exercise ASSIGNMENT -3|1 Videos

  • PYTHAGORAS THEOREM

    CHETAN PUBLICATION|Exercise Additional MCQ.s|10 Videos

  • MODEL ACTIVITY SHEET

    CHETAN PUBLICATION|Exercise QUESTION|29 Videos

  • QUADRATIC EQUATIONS

    CHETAN PUBLICATION|Exercise ASSIGNMENT|12 Videos

Similar Questions

Explore conceptually related problems

In adjoining figure, seg AD bot side BC, B-D-C. Prove that AB^(2) + CD^(2) = BD^(2) + AC^(2)

In Delta ABC, angle BAC = 90^(@), seg BL and seg CM are medians of Delta ABC prove that 4(BL^(2) + CM^(2)) = 5 BC^(2)

In Delta ABC, "seg" AD bot "seg" BC, DB = 3CD . Prove that: 2 AB^(2) = 2AC^(2) + BC^(2)

Let X be any point on side BC of DeltaABC seg XM || side AB and seg XN ||side CA . M - N- T , T - B - X . Prove that : TX^(2)=TB.TC.

Delta DEF is an "equilateral triangle"."Seg" DP bot side EF. E- P - F. "Prove that" : DP^(2) = 3EF^(2)

Delta PQR is an "equilateral triangle", "seg" PM bot side QR, Q -M- R "Prove that" : PQ^(2) = 4QM^(2)

In the adjoining figure, seg BD bot "side" AC, C-D-A. "Prove that" : AB^(2) = BC^(2) + AC^(2) - BC.AC

Solve the following sub question in Delta ABD, angle BAD = 90^(@) seg AC bot hypo BD, B - C- D show that (i) AB^(2) = BC : BD (ii) AD^(2) = BD : CD

In the adjoining figure, seg AD bot side BC, seg BE bot side AC, segCf bot side AB . Point O is the orthocentre. Prove that, point O is the incentre of DeltaDEF

CHETAN PUBLICATION-PYTHAGORAS THEOREM-PROBLEMS FOR PRACTICE
  1. In Delta XYZ, angle y = 90^(@), angle Z = a^(@), angle x = (a + 30 ^(@...

    Text Solution

    |

  2. In the adjoining figure, angle L = angle MNK = 90^(@), angle MKL = 30^...

    Text Solution

    |

  3. Sides of triangles are given below. Determine which of the them are ri...

    Text Solution

    |

  4. A ladder 10 m long reaches a window 8 m above the ground. Find the dis...

    Text Solution

    |

  5. E is a point on hypotenuse dF of Delta DFH, such that seg HE bot seg D...

    Text Solution

    |

  6. In adjoining figure, seg AD bot side BC, B-D-C. Prove that AB^(2) + CD...

    Text Solution

    |

  7. In the adjoining figure, angle PQR = 90^(@) "seg" QS bot side PR, PS =...

    Text Solution

    |

  8. Delta DEF is an "equilateral triangle"."Seg" DP bot side EF. E- P - F....

    Text Solution

    |

  9. Delta PQR is an "equilateral triangle", "seg" PM bot side QR, Q -M- R ...

    Text Solution

    |

  10. In the adjoining figure, seg BD bot "side" AC, C-D-A. "Prove that" : A...

    Text Solution

    |

  11. In Delta PQR, M is "the midpoint of" side QR. If PQ = 11, PR = 17 "and...

    Text Solution

    |

  12. In Delta ABC, AP is a "median". If AP = 7,AB^(2) + AC^(2) = 260 "find"...

    Text Solution

    |

  13. In Delta ABC, AB^(2) + AC^(2) = 122 and BC = 10 Find the length of the...

    Text Solution

    |

  14. Adjacent sides of a parallelogram are 11 cm and 17 cm. If the length o...

    Text Solution

    |

  15. If 'O' is any point in the interior of rectangle ABCD, then prove that...

    Text Solution

    |

  16. In the adjoining figure , Delta PQR is an equilateral triangle. QR = R...

    Text Solution

    |

  17. In the adjoining figure, angle PQR = 90^(@)T is the midpoint of side Q...

    Text Solution

    |