Home
Class 10
MATHS
Solve the following sub question : in ...

Solve the following sub question :
in the adjoining figure, seg `PS bat side QR. If PQ = a, PR = b QS = c and Rs = d` then complete the following activity to prove that (a + b) (a - b) = (c + d) (c - d)
Proof : In `Delta PSQ angle PSQ = 90 ^(@)`
`square^(2) = PS^(2) + square^(2)`
` PS^(2) = square^(2) - square^(2)`
In `Delta PSR, angle PSR = 90^(@)`
`square^(2) = PS^(2) + square^(2)`
`PS^(2) = square^(2) - square^(2) = square^(2) - square^(2)`
`a^(2) - c^(2) = b^(2) - d^(2)`
`a^(2) - b^(2) = C^(2) - d^(2)`
`square xx square = square xx square`

Promotional Banner

Topper's Solved these Questions

  • PYTHAGORAS THEOREM

    CHETAN PUBLICATION|Exercise ASSIGNMENT -3|1 Videos
  • PYTHAGORAS THEOREM

    CHETAN PUBLICATION|Exercise ASSIGNMENT -4|1 Videos
  • PYTHAGORAS THEOREM

    CHETAN PUBLICATION|Exercise PROBLEMS FOR PRACTICE|17 Videos
  • MODEL ACTIVITY SHEET

    CHETAN PUBLICATION|Exercise QUESTION|29 Videos
  • QUADRATIC EQUATIONS

    CHETAN PUBLICATION|Exercise ASSIGNMENT|12 Videos

Similar Questions

Explore conceptually related problems

In the adjoining figure, if PQ = 6, QR = 10, PS = 8, then find TS.

In the adjoining figure, angle PQR = 90^(@) "seg" QS bot side PR, PS = 4, PQ = 6. Find x,y and z.

Solve the following sub questions: in Delta PQR, angle PQR = 90^(@) "seg" QS bot "hypotenuse" PR, PS = 16 , RS = 9 "find" QS

In the adjoining figure , seg PQ || AB. Seg PR || seg BD. Prove that QR||AD.

In the adjoining figure "seg "PSbot"ray "RQ,"seg "QTbot"seg "PR. "If " RQ=6,PS=6andPR=12" then find "QT.

In Delta PQR, Point S is the midpoint of side QR. If PQ = 11, PR = 17, PS = 13 then find QR.

In the adjoining figure , "seg " PQ||" seg " DE, A(DeltaPQF)=20 sq units . PF = 2 , then find A(squareDPQE) by completing the following activity.

In Delta PQR, angle Q = 90^(@), PQ = QR = 5 sqrt 2 PR = 10 "then" angle P…….

Solve the any one of following sub questions: In Delta PQR, "seg" PM "is a median" PM = 10 and PQ^(2) + PR^(2) = 328 "then find" QR