" The inverse of "[[1,sin alpha],[-sin alpha,-1]]" is "

Find the inverse of [1000cos alpha sin alpha0sin alpha-cos alpha]

What is the inverse of A = ((cos alpha,sin alpha),(sin alpha,-cos alpha))

Find inverse of the matrix A=[[cos alpha, -sin alpha, 0 ],[ sin alpha, cos alpha, 0],[ 0, 0, 1]]

Find the Adjoint and Inverse of the matrix [(cos alpha,-sin alpha),(sin alpha,cos alpha)]

If 2(sin alpha)/(1+cos alpha+sin alpha)=y then value of (1-cos alpha+sin alpha)/(1+sin alpha) is

The value of the determinant ,cos alpha,-sin alpha,1sin alpha,cos alpha,1cos(alpha+beta),-sin(alpha+beta),1]| is equal

The real value of alpha for which the expression (1-sin alpha)/(1+2i sin alpha) is purely real is

Find the inverse of each of the matrices. [[1, 0, 0],[ 0 , cos alpha, sin alpha],[ 0, sin alpha, -cos alpha]]

Find the inverse the matrix (if it exists)given in [[1,0,00,cos alpha,sin alpha0,sin alpha,-cos alpha]]

If A=[[cosalpha, sin alpha] , [-sin alpha, cos alpha]] and A^(-1)=A' then alpha=