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[" A marble block of mass "2kg" lying on...

[" A marble block of mass "2kg" lying on ice when given "],[" a velocity of "6m/s" is stopped by friction in "10s" .Ther "],[" the coefficient of friction is "]

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A marble block of mass 2 kg lying on ice when given a velocity of 6m//s is stopped by friction in 10s. Then the coefficient of friction is

A marble block of mass 2 kg lying on ice when given a velocity of 6m//s is stopped by friction in 10s. Then the coefficient of friction is

A marble block of mass 2 kg lying on ice when given a velocity of 6m//s is stopped by friction in 10s. Then the coefficient of friction is

A marble block of mass 2 kg lying on ice when given a velocity of 6m//s is stopped by friction in 10s. Then the coefficient of friction is

A marble block of mass 2 kg lying on ice when given a velocity of 6 m//s is stopped by friction in 10 s. Then the coefficient of friction is:

A marble block of mass 2 kg lying on ice when given a velocity of 6 m//s is stopped by friction in 10 s. Then the coefficient of friction is -

A marble block of mass 2 kg lying on ice when given a velocity of 6ms^(-1) is stopped by friction in 10s. Then the coefficient of friction is (g = 10 ms^(-2) )