pqx^(2)-(p^(2)+q^(2))x+pq=0

sin alpha =(2pq)/(p^2+q^2) => sec alpha - tan alpha= .......... A) (p-q)/(p+q) B) (pq)/(p^(2) +q^(2)) C) (p+q)/(p-q) D) (pq)/(P+q)

The solution set of the equation pqx^(2)-(p+q)^(2)x+(p+q)^(2)=0 is

Solve the following equation for x: 9x^(2)-9(p+q)x+(2p^(2)+5pq+2q^(2))=0

If 2010 is a root of x^(2)(1 - pq) - x(p^(2) + q^(2)) - (1 + pq) = 0 and 2010 harmonic mean are inserted between p and q then the value of (h_(1) - h_(2010))/(pq(p - q)) is

If 2010 is a root of x^(2)(1 - pq) - x(p^(2) + q^(2)) - (1 + pq) = 0 and 2010 harmonic mean are inserted between p and q then the value of (h_(1) - h_(2010))/(pq(p - q)) is

Given that p = -3 and q = 2, evaluate p^(2)+(-pq^(2))-p^(2)q^(2) .

Given pq + qr + rp = 0 find (p^(2))/(p^(2)-qr) + (q^(2))/(q^(2) -rp) + (r^(2))/(r^(2) - pq)= ?