If a body cools down from `80^(@) C`to `60^(@) C` in 10 min when the temperature of the surrounding of the is `30^(@) C` . Then, the temperature of the body after next 10 min will be

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be

A body takes 10 minutes to cool from 60^(@)C to 50^(@)C . The temperature of surroundings is constant at 25^(@) C. Then, the temperature of the body after next 10 minutes will be approximately

A body takes 10min to cool from 60^(@)C " to" 50^(@0C . If the temperature of surrounding is 25^(@)C , then temperature of body after next 10 min will be

A body takes 8 min to cool from 60^@ C to 50^@C . If the temperature of sorrunding is 30^@C , then temperature of body after next 20 min. will be

The temperature of a body falls from 52^(@)C to 36^(@)C in 10 minutes when placed in a surrounding of constant temperature 20^(@)C . What will be the temperature of the body after another 10min . (Use Newton's law of cooling)

A body cools from 50^(@)C to 46^(@)C in 5 min and to 40^(@)C in the next 10 min. then the temperature of the surrounding is

A body cools in 10 min from 60^(@) C to 40^(@) C and to 42.5^(@) C in 7.5 min. Find the temperature of the surroundings.

A body takes 10 minutes to cool from 60^@C to 50^@C . If the temperature of surrounding s is 25^@C , then temperature of body after next 10 minutes will be