Assuming that four hydrogen atom combine to form a helium atom and two positrons, each of mass 0.00549u, calculate the energy released. Given `m(._(1)H^(1))=1.007825u, m(._(2)He^(4))=4.002604u`.

Calculate the energy released during the combination of four hydrogen atoms and forming a helium atom along with two positrons. Use the atomic masses given as follows: m(""_(1)H^(1)) = 1.007824 u, m(""_(2)He^(4)) = 4.002604 u and mass of each positrons = 0.000548 u.

The sun is believed to be getting its energy form the fusion of four protons to form a helium nucleus and a pair of positrons. Calculate the release of energy per fusion in MeV. Mass of proton=1.007825 a.m.u. , mass of positron =0.000549 a.m.u., mass of helium nucleus =4.002603 a.m.u. Take 1a.m.u. =931MeV.

In a fusion reactor, the reaction occurs in two stages. (i) Two deuterium (""_(1)^(2)D) nuclei fuse to form a tritium (""_(1)^(3)T) nucleus with a proton as product. (ii) A tritium nucleus fuses with another deuterium nucleus to form a helium (""_(2)^(4)He) nucleus with neutron as another product. Find (a) the energy released in each stage. (b) the energy released in the combined reaction per deuterium and (c) what percentage of the mass energy of the initial deuterium is released? Given : ""_(1)^(2)D=2.014102u,""_(1)^(3)T=3.016049u,""_(2)^(4)He=4.002603u,""_(1)^(1)H=1.007825u,""_(0)^(1)n=1.008665u Take 1u = 931 MeV

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particle) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u. = 931 MeV) .

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particle) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u. = 931 MeV) .