" is "0.85.

Represent the following decimals as percentages. (i) 2.30" "(ii) 0.85

A sample of H_2O_2 is labelled "11.2 volume". The volume of this sample which contains 0.85 g H_2O_2 .

A sample of H_2O_2 is labelled "11.2 volume". The volume of this sample which contains 0.85 g H_2O_2 .

A bowler whose bowling average is 24.85 runs per wicket, takes 5 wickets for 52 runs in next inning and thereby decreases his average by 0.85. Find the number of wickets before last match.

A cricketer whose bowling average is 24.85, runs per wicket, takes 5 wickets for 52 runs and thereby decreases his average by 0.85. The number of wickets taken by him till the last match was :

Prove that (0.85xx0.85xx0.85+0.15xx0.15xx0.15)/(0.85xx0.85-0.85xx0.15+0.15xx0.15)=1