[12.(15)/(3)+(2)/(y)=17],[(1)/(5)+(1)/(y)=(36)/(5)]

Solve i 12(2)/(15)-:1(7)/(17)-(11)/(15)= ii) (2)/(3)-:(4)/(15)-1.9= Rewrite in improper fraction (462)/(88)

The area bounded by the region between curves y=x^(2)+2,x=0,x=3,y=x+1 is s(A)(15)/(2)(B)(15)/(4)(C)(15)/(3)(D)(17)/(2)

Simplify: 10(1)/(8) of (12)/(15)-:(35)/(36) of (20)/(49)*( a) 17(5)/(12) (b) 17(8)/(17) (c) 20(3)/(25) (d) 20(103)/(250)

Which one of the following is true? 1/2<9/(13)<3/4<(12)/(17) (b) 3/4<9/(13)<1/2<(12)/(17) (c) 1/2<3/4<9/(13)<(12)/(17) (d) 1/2<9/(13)<(12)/(17)<3/4

The point from which the tangents to the circle x^2 + y^2 - 4x - 6y - 16 = 0, 3x^2 + 3y^2 - 18x + 9y + 6 = 0 and x^2 + y^2 - 8x - 3y + 24 = 0 are equal in length is : (A) (2/3, 4/17) (B) (17/16, 4/15) (C) (17/16, 4/15) (D) (5/4, 2/3)

(12x + 17) / (3x + 1)-(2x + 15) / (x + 7) = 3 (1) / (5), x! =-(1) / (3), -7

Solve: (12x+17)/(3x+1)-(2x+15)/(x+7) = 3 1/5[x!= -1/3,-7]

The reflection of the point (2,-1,3) in the plane 3x-2y-z=9 is (A) (28/7,15/7,17/7) (B) (26/7,-15/7,17/7) (C) (15/7,26/,-17/7) (D) (26/7,17/7,-15/70)