Home
Class 11
MATHS
If the line (x/a)+(y/b)=1 moves in such ...

If the line `(x/a)+(y/b)=1` moves in such a way that `(1/(a^2))+(1/(b^2))=(1/(c^2))` , where `c` is a constant, prove that the foot of the perpendicular from the origin on the straight line describes the circle `x^2+y^2=c^2dot`

Promotional Banner

Similar Questions

Explore conceptually related problems

if (x)/(a)+(y)/(b)=1 is a variable line where (1)/(a^(2))+(1)/(b^(2))=(1)/(c^(2))(c is constant ) then the locus of foot of the perpendicular drawn from origin

Find the coordinates of the foot of the perpendicular drawn from the point (1,-2) on the line y=2x+1

Let a o* b be any two numbers satisfying (1)/(a^(2))+(1)/(b^(2))=(1)/(4) .Then,the foot of the perpendicular from the origin on variable line (x)/(a)+(y)/(b)=1 lies on

If 2p is the length of perpendicular from the origin to the lines (x)/(a)+(y)/(b)=1, then a^(2),8p^(2),b^(2) are in

The perpendicular drawn from origin to the line y=mx+c meets the line at point (-1,-2) , (c,m)=?