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Find the number of real ordered pair(s) ...

Find the number of real ordered pair(s) (x, y) for which: `16^(x^2+y) + 16^(x+y^2) = 1`

A

0

B

1

C

2

D

3

Text Solution

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The correct Answer is:
B
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VK JAISWAL-FUNCTION -SUBJECTIVE TYPE PROBLEMS
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  3. Let f (x) =x ^(3)-3x Find f (f (x))

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  4. If f(x+y+1)={sqrt(f(x))+sqrt(f(y))}^2 and f(0)=1AAx ,y in R ,d e t e ...

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  5. If the domain of f(x) = sqrt (12-3^(x)-3^(3-x))+ sin ^(-1) ((2x)/(3 ...

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  6. The number of elements in the range of functions: y=sin^(-1) [x^(2)+5/...

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  7. The number of integers in the range of function f(x)= [sinx] + [cosx] ...

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  8. If P (x) is polynomial of degree 4 such than P (-1)=P (1) =5 and P (-2...

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  10. Let the solution set of the equation sqrt([x+[x/2]])+[sqrt({x})+[x/3]]...

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  18. Let f(x) be a continuous function such that f(0) = 1 and f(x)=f(x/7)=x...

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