Home
Class 12
MATHS
Let f(x)=2-|x-3|,1<= x <= 5 and for rest...

Let `f(x)=2-|x-3|,1<= x <= 5` and for rest of the values f(x) can be obtained by using the relation `f(5x)=alpha f(x) AA x in R` The maximum value of `f(x)` in `[5^4,5^5]` for `alpha=2` is

A

16

B

32

C

64

D

8

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • FUNCTION

    VK JAISWAL|Exercise MATCHING TYPE PROBLEMS|7 Videos

  • FUNCTION

    VK JAISWAL|Exercise SUBJECTIVE TYPE PROBLEMS|34 Videos

  • FUNCTION

    VK JAISWAL|Exercise ONE OR MORE THAN ONE ANSWER IS/ARE CORRECT|25 Videos

  • ELLIPSE

    VK JAISWAL|Exercise Exercise-4 : Subjective Type Problems|2 Videos

  • HYPERBOLA

    VK JAISWAL|Exercise Exercise-4 : Subjective Type Problems|3 Videos

Similar Questions

Explore conceptually related problems

Let f(x)=|x^(2)-3x-4|,-1lexle4. Then

Let f (x) =(2 |x| -1)/(x-3) Range of f (x):

Let f(x)=|x^(2)-3x-4|,-1<=x<=4 Then f(x) is monotonically increasing in [-1,(3)/(2)]f(x) monotonically decreasing in ((3)/(2),4) the maximum value of f(x) is (25)/(4) the minimum value of f(x) is 0

Let f(x)=x^(2)-3x+1 if c_(1) and c_(2) are two values of c for which tangent line to graph of f(x) at point (c,f(c)) intersects x axis at (3,0) then (c_(1)+c_(2)) is

Let f (x) =(2 |x| -1)/(x-3) Range of the values of 'k' for which f (x) = k has exactly two distinct solutions:

Let f(x)=|x-1|+|2x-1|+|3x-1|+......+|119x-1| If 'm' denotes the minimum value of f(x) the sqrt(m)sqrt(m) equals is

Let f(x)=|x-1|+|2x-1|+|3x-1|+......+|119x-1| If 'm' denotes the minimum value of f(x) the sqrt(m)sqrt(m) equals is

Let f(x)=2x^(3)+3(1-3a)x^(2)+6(a^(2)-a)x+b where a,b in R. Find the smallest integral value of a for which f(x) has a positive point of local maximum.

Let f(x)={2x-1,-3 le x lt 1,3x^(^^)2-2, x ge 1 and g(x)=4x+7-5 le 0,5x^(^^)2-x+7x>=0 then value of int_(-)(-2)^(^^)2gof(x) equals