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If f (x) =2x, g (x) =3 sin x -x cos x, t...

If `f (x) =2x, g (x) =3 sin x -x cos x, then ` for `x in (0, (pi)/(2)):`

A

`f (x) gt g (x)`

B

`f (x) lt g (x)`

C

`f (x)=g (x)` has exactly one real root.

D

`f (x) =g (x)` has exactly two real roots

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The correct Answer is:
A
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VK JAISWAL-APPLICATION OF DERIVATIVES -EXERCISE (SUBJECTIVE TYPE PROBLEMS)
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