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Let `f (x)` be function defined on `[0,1] ` such that `f (1)=0` and for any `a in (0,1], int _(0)^(a) f (x) dx - int _(a)^(1) f (x) dx =2 f (a) +3a +b` where b is constant.
`int _(0)^(1) f (x) dx =`

A

`1/e`

B

`(1)/(2e)`

C

`(3)/(2e)`

D

`(2)/(e)`

Text Solution

Verified by Experts

The correct Answer is:
C
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