Home
Class 12
MATHS
A basket ball team consists of 12 pairs ...

A basket ball team consists of 12 pairs of twin brothers. On the first day of training, all 24 players stand in a circle in such a way that all pairs of twin brothers are neighbours. Number of ways this can be done is :

A

` (12)!2^(11) `

B

` (11)!2^(12) `

C

` (12)!2^(12) `

D

` (11)!2^(11) `

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • PERMUTATION AND COMBINATIONS

    VK JAISWAL|Exercise Exercise-2 : One or More than One Answer is/are Correct|4 Videos

  • PERMUTATION AND COMBINATIONS

    VK JAISWAL|Exercise Exercise-3 : Comprehension Type Problems|2 Videos

  • PARABOLA

    VK JAISWAL|Exercise Exercise-5 : Subjective Type Problems|3 Videos

  • PROBABILITY

    VK JAISWAL|Exercise Exercise -5 : Subjective Type problems|12 Videos

Similar Questions

Explore conceptually related problems

52 cards are to be distributed among 4 players such that 2 players get 12 cards each and other 2 players get 14 cards each,then the number of ways in which this can be done is

There are 3 oranges, 5 apples and 6 mangoes in a fuit basket (all fruits of same kind are identical). Number of ways in which fruits can be selected from the basket, is

There are fifty persons among whom 2 are brothers. The number of ways they can be arranged in a circle, if there is exactly one person between the two brothers, is

Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue.Let m be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue.Then the value of m/n is

There are 20 persons among whom are two brothers. The number of ways in which we can arrange them around a circle so that there is exactly one person between the two brothers, is

The number of ways can seven persons sit around a table so that all shall not have the same neighbours in any two arrangements is

Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue.Let m be the number in which 5 boys and 5 girls stand in such a way that exactly four girls stand consecutively in the queue. Then the value of (m)/(n) is

Find the number of ways in which six persons can be seated at a round table,so that all shall not have the same neighbours n any two arrangements.

There are 6 balls of different colours and 3 boxes of different sizes. Each box can hold all the 6 balls. The balls are put in the boxes so that no box remains expty. The number of ways in which this can be done is (A) 534 (B) 543 (C) 540 (D) 28