Home
Class 12
MATHS
In a parallelogram PQRS (taken in order)...

In a parallelogram PQRS (taken in order), P is the point (-1, -1), Q is (8, 0) and R is (7, 5). Then S is the point :

A

`(-1, 4)`

B

`(-2, 2)`

C

`(-2, (7)/(2))`

D

`(-2, 4)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    VK JAISWAL|Exercise Exercise-2 : One or More than One Answer is/are Correct|12 Videos
  • STRAIGHT LINES

    VK JAISWAL|Exercise Exercise-3 : Comprehension Type Problems|4 Videos
  • SOLUTION OF TRIANGLES

    VK JAISWAL|Exercise Exercise-5 : Subjective Type Problems|13 Videos
  • TRIGONOMETRIC EQUATIONS

    VK JAISWAL|Exercise Exercise-5 : Subjective Type Problems|9 Videos

Similar Questions

Explore conceptually related problems

Consider the points P(2,-4):Q(4,-2) and R(7,1). The points P,Q,R

Vertices of a parallelogram taken in order are A, ( 2,-1,4) , B (1,0,-1) , C ( 1,2,3) and D. Distance of the point P ( 8, 2,-12) from the plane of the parallelogram is

ABCD is rectangle formed by the points A(-1, -1), B(-1, 4), C(5, 4) and D(5, -1). If P, Q, R and S be the midpoint of AB, BC, CD and DA respectively, show that PQRS is a rhombus.

Find the value of k for which the points P(5, 5), Q(k, 1) and R(11, 7) are collinear

In the given figure, PQRS is a straight line R is the mid-point of QS and Q is the mid-point of PS. S is (6,5), R is (3, 5) and T is (4,8). Find the length of median TU. QRS

The point P (3,2,4),Q(4,52),R(5,8,0) and S(2,-1,6) are :

The points P(3,2,4), Q(4,5,2), R(5,8,0) and S(2,-1,6) are

Find the distance between the points P(-1,1) and Q(5, -7)