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Circum radius of a DeltaABC is 3 units, ...

Circum radius of a `DeltaABC` is 3 units, let O be the circum and H be the orthocentre then the value of `(1)/(64)(AH^(2)+BC^(2))(BH^(2)+AC^(2))(CH^(2)+AB^(2))` equals :

A

`3^(4)`

B

`9^(3)`

C

`27^(6)`

D

`81^(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
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